document.write( "Question 26398: please help me solve this using substitution, I don't understand how to work any of these linear equations by substitution or elimination.
\n" ); document.write( " x + 3y = 3
\n" ); document.write( " 2x + 3y = 0
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Algebra.Com's Answer #14282 by Alwayscheerful(414)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cx+%2B+3%5Cy+=+3%2C%0D%0A++++2%5Cx+%2B+3%5Cy+=+0+%29%0D%0A++\"We'll use substitution. After moving 3*y to the right, we get:
\n" ); document.write( " \"1%2Ax+=+3+-+3%2Ay\", or \"x+=+3%2F1+-+3%2Ay%2F1\". Substitute that
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\n" ); document.write( " \"2%2A%283%2F1+-+3%2Ay%2F1%29+%2B+3%5Cy+=+0\" and simplify: So, we know that y=2. Since \"x+=+3%2F1+-+3%2Ay%2F1\", x=-3.
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\n" ); document.write( " Answer: \"system%28+x=-3%2C+y=2+%29\".
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Solved by pluggable solver: Linear System solver (using determinant)
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cx+%2B+3%5Cy+=+3%2C%0D%0A++++2%5Cx+%2B+3%5Cy+=+0+%29%0D%0A++\"
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\n" ); document.write( " Any system of equations:
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\n" ); document.write( " has solution
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\n" ); document.write( " (x=-3, y=2}
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\n" ); document.write( "\n" ); document.write( "Hope this helps!
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