document.write( "Question 190296: Hi.\r
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document.write( "I need some help reducing this rational expression completely:\r
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document.write( "n^3 - 1/n^2 - 1\r
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document.write( "thanks! \n" );
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Algebra.Com's Answer #142819 by feliz1965(151)![]() ![]() ![]() You can put this solution on YOUR website! In the numerator, we have the difference of two cubes.\r \n" ); document.write( "\n" ); document.write( "a^3 – b^3 = (a – b)(a^2 + ab + b^2)\r \n" ); document.write( "\n" ); document.write( "Let a = n\r \n" ); document.write( "\n" ); document.write( "Using this rule, the numerator becomes \r \n" ); document.write( "\n" ); document.write( "n^3 - 1 = (n - 1)(n^2 + n(-1) + (-1)^2)\r \n" ); document.write( "\n" ); document.write( "n^3 - 1 = (n - 1)(n^2 - n + 1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The denominator is the difference of two perfect squares.\r \n" ); document.write( "\n" ); document.write( "n^2 - 1 = (n - 1)(n + 1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We now have this fraction:\r \n" ); document.write( "\n" ); document.write( "[(n - 1)(n^2 - n + 1)]/(n - 1)(n + 1)\r \n" ); document.write( "\n" ); document.write( "We can cancel like terms located in the numerator and denominator.\r \n" ); document.write( "\n" ); document.write( "In this question, that means removing (n - 1).\r \n" ); document.write( "\n" ); document.write( "Final answer: (n^2 - n + 1)]/(n + 1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |