document.write( "Question 190294: A signal flare is fired upward with initial speed 245m/s. A stationary balloonist at the height of 1960 m sees the flare pass on the way up. How long after this will the flare pass the balloonist again on the way down?\r
\n" ); document.write( "\n" ); document.write( "This is for my son, and yes, I'm a few years out of practice. He's tried setting it to zero with: -4.9t^2-245t+1960=0. I think h=rt-4.9t^2 is the formula was also given to him. Can you help, please? He knows the answer is 30 seconds, but can't show the work. Thanks
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Algebra.Com's Answer #142808 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Well, first off, the equation should be \"-4.9t%5E2%2B245t=1960\" (let me know if you need help figuring out the equation)\r
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\n" ); document.write( "\n" ); document.write( "\"-4.9t%5E2%2B245t=1960\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-4.9t%5E2%2B245t-1960=0\" Subtract 1960 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-49t%5E2%2B2450t-19600=0\" Multiply EVERY term by 10 to make every number a whole number.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"at%5E2%2Bbt%2Bc\" where \"a=-49\", \"b=2450\", and \"c=-19600\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for t\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( " Plug in \"a=-49\", \"b=2450\", and \"c=-19600\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-2450+%2B-+sqrt%28+6002500-4%28-49%29%28-19600%29+%29%29%2F%282%28-49%29%29\" Square \"2450\" to get \"6002500\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-2450+%2B-+sqrt%28+6002500-3841600+%29%29%2F%282%28-49%29%29\" Multiply \"4%28-49%29%28-19600%29\" to get \"3841600\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-2450+%2B-+sqrt%28+2160900+%29%29%2F%282%28-49%29%29\" Subtract \"3841600\" from \"6002500\" to get \"2160900\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-2450+%2B-+sqrt%28+2160900+%29%29%2F%28-98%29\" Multiply \"2\" and \"-49\" to get \"-98\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-2450+%2B-+1470%29%2F%28-98%29\" Take the square root of \"2160900\" to get \"1470\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-2450+%2B+1470%29%2F%28-98%29\" or \"t+=+%28-2450+-+1470%29%2F%28-98%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-980%29%2F%28-98%29\" or \"t+=++%28-3920%29%2F%28-98%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+10\" or \"t+=+40\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"t+=+10\" or \"t+=+40\" \r
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\n" ); document.write( "\n" ); document.write( "This means that at 10 seconds the flare is at the height of 1960 m. Also, the flare is 1960 m high when the time is 40 seconds. \r
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\n" ); document.write( "\n" ); document.write( "So the difference between these two times is 40-10=30 seconds (think of t=10 as time zero for the balloonist)\r
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\n" ); document.write( "\n" ); document.write( "So it takes 30 seconds for the flare to come back down to the height of 1960 m.
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