document.write( "Question 3274: SORRY! I caught a typo error in my question!! Given: h=-16 t squared +vt+ s, a ball can be thrown at 40 ft/s. Set the initial height at 0.
\n" ); document.write( "1. a.) When will the ball reach a height of 24 feet?
\n" ); document.write( " b.) When does the ball hit the ground?\r
\n" ); document.write( "\n" ); document.write( "2.) a.) If the ball is thrown at 64 ft/s, when will it reach 48 feet?
\n" ); document.write( " b.) When does the ball hit the ground?
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Algebra.Com's Answer #1428 by khwang(438)\"\" \"About 
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h=-16 t^2 +vt+ s, s = 0,
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\n" ); document.write( " 1.a) v = 40 ft/s
\n" ); document.write( " When h = 24, solve the equation 24 = -16 t^2 + 40t or
\n" ); document.write( " 2t^2 - 5t + 3 = 0,
\n" ); document.write( " Factoring (2t -3)(t - 1) = 0, so t = 1 or 3/2
\n" ); document.write( " Hence, when t = 1 or 1.5 sec, h = 24 ft
\n" ); document.write( " b) The height of the ground is h = 0, solve
\n" ); document.write( " -16 t^2 + 40t = 0 or 8t(2t -5) = 0.
\n" ); document.write( " So, t = 5/2 or 0(means initial)
\n" ); document.write( " Hence, when t = 2.5 sec, it hits the ground.
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\n" ); document.write( " 2.a) v = 64 ft/s
\n" ); document.write( " When h = 48, solve the equation 48 = -16 t^2 + 64t or
\n" ); document.write( " t^2 - 4t + 3 = 0,
\n" ); document.write( " Factoring (t -3)(t - 1) = 0, so t = 1 or 3
\n" ); document.write( " Hence, when t = 1 or 3 sec, h = 48 ft
\n" ); document.write( " b) The height of the ground is h = 0, solve
\n" ); document.write( " -16 t^2 + 64t = 0 or 16t(t -4) = 0.
\n" ); document.write( " So, t = 4 or 0(means initial)
\n" ); document.write( " Hence, when t = 4 sec, it hits the ground.\r
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\n" ); document.write( "\n" ); document.write( " Kenny
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