document.write( "Question 190270: The rate, given that the distance is 200 ft and the time is x+3 seconds
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Algebra.Com's Answer #142784 by jim_thompson5910(35256)\"\" \"About 
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\"d=rt\" Start with the distance rate time equation\r
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\n" ); document.write( "\n" ); document.write( "\"200=r%28x%2B3%29\" Plug in \"d=200\" and \"t=x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"200%2F%28x%2B3%29=r\" Divide both sides by \"x%2B3\".\r
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\n" ); document.write( "\n" ); document.write( "\"r=200%2F%28x%2B3%29\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "So the rate is \"200%2F%28x%2B3%29\" feet per second
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