document.write( "Question 189988: 2. Choose the equation of the parabola with a vertex at the origin and a focus at (0, –3).\r
\n" ); document.write( "\n" ); document.write( "1. y=-1/3x
\n" ); document.write( "2. y=1/12x^2
\n" ); document.write( "3. y=-1/3x^2
\n" ); document.write( "4. y=1/12x^2
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Algebra.Com's Answer #142686 by cutepiscean5(19)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "we have the vertex as (0,0) and focus as (0,-3) , since the x-coordinate of both the vertex and focus are the same, it means the parabola is a vertical parabola.\r
\n" ); document.write( "\n" ); document.write( "The form of a vertical parabola is given by:\r
\n" ); document.write( "\n" ); document.write( "\"+4p%28y-k%29+=+%28x-h%29%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "where (h,k) is the vertex (here it is (0,0))
\n" ); document.write( "p = distance between the vertex and the focus of the parabola.\r
\n" ); document.write( "\n" ); document.write( "we are given the coordinates of focus as (0,-3), thus the y-coordinate here is equivalent to k + p\r
\n" ); document.write( "\n" ); document.write( "=> \"+-3+=+0+%2B+p+\"
\n" ); document.write( "=> \"+p+=+-3+\"\r
\n" ); document.write( "\n" ); document.write( "we plug in all the values into the equation and get:\r
\n" ); document.write( "\n" ); document.write( "\"+4%2A%28-3%29%28y-0%29+=+%28x-0%29%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "simplifying further we get:\r
\n" ); document.write( "\n" ); document.write( "\"+-12%2Ay+=+x%5E2+\"
\n" ); document.write( "=> \"+y+=+-1%2F12%2Ax%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "so out of choices 2 and 4 which ever corresponds to our answer is the correct one. (there is a misprint in the choices that has been given for 2 and 4)\r
\n" ); document.write( "\n" ); document.write( "Hope this helps you.
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