document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=190102>Question 190102</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780136007319/algebrahomeworkh>Beginning & Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 feet longer than the width. The permineter is 30 feet. Find the dimensions of the rectangle.<BR>\n" );
document.write( "a. length = 8 feet; width = 5 feet<BR>\n" );
document.write( "b. length = 8 feet; width = 7 feet<BR>\n" );
document.write( "c. length = 9 feet; width = 6 feet </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142681 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2w<BR>\n" );
document.write( ".<BR>\n" );
document.write( "L=w+3<BR>\n" );
document.write( "2(w+3)+2w=30 Substitute w+3 for L<BR>\n" );
document.write( "2w+6+2w=30<BR>\n" );
document.write( "4w=24<BR>\n" );
document.write( "w=6<BR>\n" );
document.write( "L=9<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );