document.write( "Question 190085: Solve each equation 10b^2-15b=8b-12 Thank you \n" ); document.write( "
Algebra.Com's Answer #142654 by bsmath(21)\"\" \"About 
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10b^2-15b=8b-12 \r
\n" ); document.write( "\n" ); document.write( "Subtract the right-hand side of the equation from both sides: \r
\n" ); document.write( "\n" ); document.write( "10b^2-15b-8b+12=0 \r
\n" ); document.write( "\n" ); document.write( "Now combine like terms: \r
\n" ); document.write( "\n" ); document.write( "10b^2-23b+12=0 \r
\n" ); document.write( "\n" ); document.write( "Now it looks like we need the quadratic formula: \r
\n" ); document.write( "\n" ); document.write( "-b/2a +-((b^2-4ac)^1/2)/2a, where a is the coeffient of the b^2 term,
\n" ); document.write( "b is the coefficient of the b term, and c is the coefficient of the
\n" ); document.write( "integer term. So, a=10, b=-23, and c=12. Plugging in the values gives us: \r
\n" ); document.write( "\n" ); document.write( "b=23/20 +- (((-23)^2-(4)(10)(12))^1/2)/20. We now have
\n" ); document.write( "23/20 +-((529-480)^1/2)/20=23/20 +-((49)^1/2)/20=
\n" ); document.write( "23/20 +-7/20=30/20, 16/20=3/2, 4/5. Check the answer by plugging in the
\n" ); document.write( "values: 10(3/2)^2-23(3/2)+12=0, 90/4-69/2+12=90/4-138/4=12=-48/4+48/4=0.
\n" ); document.write( "You can check the second result the same way.
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