document.write( "Question 26400: Mandy is now twice Katy's age. In six years she will be 1.5 times Katy's age.\r
\n" ); document.write( "\n" ); document.write( "How old is Katy \n" ); document.write( "
Algebra.Com's Answer #14258 by Paul(988)\"\" \"About 
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Since Mandy is twice as old as cathy, you know that there is one variable to consider, because due supportment.
\n" ); document.write( "Kathy's age = x
\n" ); document.write( "Mandy's age = 2x
\n" ); document.write( "In six years Kathy's age = x+6
\n" ); document.write( "In six years Mandy's age = 2x+6
\n" ); document.write( "And since she will be 1.5 the quanity of Kathy in SIX years we write.
\n" ); document.write( "1.5(x+6) Expression 1
\n" ); document.write( "And Mandy herself is 2x+6 Expression 2.
\n" ); document.write( "Expression 1 = Expression 2.
\n" ); document.write( "1.5(x+6)=2x+6
\n" ); document.write( "1.5x+9=2x+6
\n" ); document.write( "0.5x=3
\n" ); document.write( "x=6 -----> Kathy's age.
\n" ); document.write( "2(6)=12 --> Mandy's age. \r
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\n" ); document.write( "\n" ); document.write( "Check: Kathy's age in 6 years = 6+6=12
\n" ); document.write( "Mandy's age in 6 years = 12+6=18
\n" ); document.write( "And 12*1.5=18
\n" ); document.write( "or 18/1.5=12\r
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\n" ); document.write( "\n" ); document.write( "Hence, Kathy is 6 years old, and Mandy is 12 years old.
\n" ); document.write( "Paul.
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