document.write( "Question 189960This question is from textbook saxon algebra 2
\n" ); document.write( ": Write the equation of the circle that has a diameter whose endpoints are located at (-2,-1) and (4,-1). \n" ); document.write( "
Algebra.Com's Answer #142541 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "
\n" ); document.write( "We know the Standard Eqn of a circle ---> \"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let us see the circle with endpoints A(-2,-1) & B(4,-1). In doing so, we get the midpoint at x & y:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "X: \"%28x%5B1%5D%2Bx%5B2%5D%29%2F2=%28-2%2B4%29%2F2=2%2F2=red%281%29\"
\n" ); document.write( "Y: \"%28y%5B1%5D%2By%5B2%5D%29%2F2=%28-1%2B%28-1%29%29%2F2=-2%2F2=red%28-1%29\"
\n" ); document.write( "Midpoint: (1,-1)--> (h,k)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "For the radius = (1/2)*Diameter\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And the Diameter equals the Distance of the endpoints A and B.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D%5E2=%28y%5B2%5D-y%5B1%5D%29%5E2%2B%28x%5B2%5D-x%5B1%5D%29%5E2\"
\n" ); document.write( "
\n" ); document.write( "\"D=sqrt%2836%29=6\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And, \"radius=%281%2F2%29D=%281%2F2%29%286%29=red%283%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Therefore, it follows---> \"%28x-1%29%5E2+%2B+%28y-%28-1%29%29%5E2+=3%5E2\"} ---> \"red%28%28x-1%29%5E2%2B%28y%2B1%29%5E2=9%29\", Answer\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
\n" ); document.write( "
\n" );