document.write( "Question 189944This question is from textbook
\n" ); document.write( ": How do I solve this proportion problem?
\n" ); document.write( "3 over 5 over b equals 8 over 5
\n" ); document.write( "I know I need to cross multiply somewhere I'm just not sure where?
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Algebra.Com's Answer #142522 by cutepiscean5(19)\"\" \"About 
You can put this solution on YOUR website!
we have the equation as:\r
\n" ); document.write( "\n" ); document.write( "\"+%283%2F5%29%2Fb+=+8%2F5+\"\r
\n" ); document.write( "\n" ); document.write( "we know that b can also be written as b over 1, that is b/1.\r
\n" ); document.write( "\n" ); document.write( "so the equation becomes;\r
\n" ); document.write( "\n" ); document.write( "\"+%283%2F5%29%2F%28b%2F1%29+=+8%2F5+\"\r
\n" ); document.write( "\n" ); document.write( "we also know the concept of reciprocals that:
\n" ); document.write( "\"+%28a%2Fb%29%2F%28c%2Fd%29+=+%28a%2Fb%29+%2A+%28d%2Fc%29+\"\r
\n" ); document.write( "\n" ); document.write( "so we first we reduce our equation as:\r
\n" ); document.write( "\n" ); document.write( "\"+3%2F5+%2A+1%2Fb+=+8%2F5+\"\r
\n" ); document.write( "\n" ); document.write( "or, \"+3%2F%285%2Ab%29+=+8%2F5+\"
\n" ); document.write( "now cross multiply, we get:\r
\n" ); document.write( "\n" ); document.write( "\"+3%2A5+=+%285%2Ab%29+%2A+8+\"
\n" ); document.write( "=> \"+15+=+40%2Ab+\"
\n" ); document.write( "=> \"+b+=+15%2F40+\"
\n" ); document.write( "=> \"+b+=+3%2F8+\" (in the lowest fraction terms)\r
\n" ); document.write( "\n" ); document.write( "so, that's our answer.
\n" ); document.write( "Hope this helps you.
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