document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189945>Question 189945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ounces of pure gold must be added to five ounces of something that is 1 % gold in order that the mixture is 6% gold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142517 by </B><A HREF=/tutors/aboutme.mpl?userid=cutepiscean5><B>cutepiscean5(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cutepiscean5><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the amount of pure gold to be added by x ounces,<BR>\n" );
document.write( "and we know that the amount of something that is 1% gold is 5 ounces.\r<BR>\n" );
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document.write( "The total amount of the mixture would then be  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B5%29 ALIGN=MIDDLE  ALT=\"%28x%2B5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > ounces\r<BR>\n" );
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document.write( "We know that pure gold is 100 % gold, and this x amount will be added to 5 ounces of 1 % gold to make the total amount of 6 % gold. So the resultant equation will be:\r<BR>\n" );
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document.write( " 100 % (x) + 1 % (5) = 6 % (x+5) \r<BR>\n" );
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document.write( "using this equation we solve for x.\r<BR>\n" );
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document.write( "The above equation becomes:\r<BR>\n" );
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document.write( "Canceling the percent from the whole equation or multiplying the whole equation by 100 we get:\r<BR>\n" );
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document.write( " 100x + 5 = 6(x+5) \r<BR>\n" );
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document.write( "=> 100x + 5 = 6x + 30 (using distributive law to open the brackets on the right hand side)\r<BR>\n" );
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document.write( "=> 100x - 6x = 30 - 5  (shifting the x-terms to the LHS and constant terms to the RHS.\r<BR>\n" );
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document.write( "=> 94x = 25 <BR>\n" );
document.write( " => x = 25/94  <BR>\n" );
document.write( "or,  x = 0.266 ounces \r<BR>\n" );
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document.write( "Thus, 0.266 ounces of pure gold must be added to five ounces of something that is 1 % gold in order that the mixture is 6% gold.<BR>\n" );
document.write( " </SPAN>\n" );
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