document.write( "Question 189904: Solve by completing the square.
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\n" ); document.write( " y^2 - 12y = -11 \n" ); document.write( "
Algebra.Com's Answer #142491 by nerdybill(7384)\"\" \"About 
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y^2 - 12y = -11
\n" ); document.write( "(y^2 - 12y + __ ) = -11
\n" ); document.write( "where the blank is 1/2 time 'b' squared:
\n" ); document.write( "(y^2 - 12y + 36 ) = -11 + 36
\n" ); document.write( "(y^2 - 12y + 36 ) = 25
\n" ); document.write( "(y^2 - 6)^2 = 25
\n" ); document.write( "Take the square root of both sides:
\n" ); document.write( "y^2 - 6 = 5
\n" ); document.write( "y^2 = 11
\n" ); document.write( "y = sqrt(11)\r
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