document.write( "Question 189835: Factor completely\r
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Algebra.Com's Answer #142427 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"3x%5E2%2B30x%2B75\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2%2B10x%2B25%29\" Factor out the GCF \"3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"x%5E2%2B10x%2B25\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"x%5E2%2B10x%2B25\" we can see that the first term is \"x%5E2\" and the last term is \"25\" where the coefficients are 1 and 25 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient 25 to get 25. Now what two numbers multiply to 25 and add to the middle coefficient 10? Let's list all of the factors of 25:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 25:\r
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\n" ); document.write( "\n" ); document.write( "-1,-5 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 25\r
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\n" ); document.write( "\n" ); document.write( "5*5\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-25)\r
\n" ); document.write( "\n" ); document.write( "(-5)*(-5)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 10? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 10\r
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First NumberSecond NumberSum
1251+25=26
555+5=10
-1-25-1+(-25)=-26
-5-5-5+(-5)=-10
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 5 and 5 add up to 10 and multiply to 25\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"x%5E2%2B10x%2B25\", replace \"10x\" with \"5x%2B5x\" (notice \"5x%2B5x\" adds up to \"10x\". So it is equivalent to \"10x\")\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%285x%2B5x%29%2B25\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"x%5E2%2B5x%2B5x%2B25\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B5x%29%2B%285x%2B25%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B5%29%2B5%28x%2B5%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"5\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%28x%2B5%29\" Since we have a common term of \"x%2B5\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2%2B5x%2B5x%2B25\" factors to \"%28x%2B5%29%28x%2B5%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"x%5E2%2B10x%2B25\" factors to \"%28x%2B5%29%28x%2B5%29\" (since \"x%5E2%2B10x%2B25\" is equivalent to \"x%5E2%2B5x%2B5x%2B25\")\r
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\n" ); document.write( "\n" ); document.write( "note: \"%28x%2B5%29%28x%2B5%29\" is equivalent to \"%28x%2B5%29%5E2\" since the term \"x%2B5\" occurs twice. So \"x%5E2%2B10x%2B25\" also factors to \"%28x%2B5%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So \"3%28x%5E2%2B10x%2B25%29\" factors down to \"3%28x%2B5%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"3x%5E2%2B30x%2B75\" completely factors to \"3%28x%2B5%29%5E2\"
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