document.write( "Question 189781: Two planes leave Chicago at the same time heading in opposite directions. The plane heading west has a tail wind and is going 25 mph faster than the other plane. If after one hour the planes are 575 miles apart, what are their speeds? \n" ); document.write( "

Algebra.Com's Answer #142400 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let r=rate of east bound plane
\n" ); document.write( "Then r+25=rate of west bound plane
\n" ); document.write( "Distance east bound plane travels=r*1
\n" ); document.write( "Distance west bound plane travels=(r+25)*1
\n" ); document.write( "The above two distances must add up to 575 mi, so:\r
\n" ); document.write( "\n" ); document.write( "r*1+(r+25)*1=575 or
\n" ); document.write( "r+r+25=575 subtract 25 from both sides
\n" ); document.write( "r+r+25-25=575-25 collect like terms
\n" ); document.write( "2r=550 divide each side by 2
\n" ); document.write( "r=275 mph---------------------------rate of east bound plane
\n" ); document.write( "r+25=275+25=300 mph-------------------rate of west bound plane\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "275*1+300*1=575
\n" ); document.write( "575=575\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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