document.write( "Question 189723: A box has dimensions that have consecutive numbers for its length, width and height, the height having the smallest of the three dimensions. If the length and width are increased by 2 cm and the height is doubled, the volume now becomes 192 cm3 greater than the original box. What are the dimensions of the original box? \n" ); document.write( "
Algebra.Com's Answer #142369 by stanbon(75887)\"\" \"About 
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A box has dimensions that have consecutive numbers for its length, width and height, the height having the smallest of the three dimensions. If the length and width are increased by 2 cm and the height is doubled, the volume now becomes 192 cm3 greater than the original box. What are the dimensions of the original box?
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\n" ); document.write( "Let the dimensions be \"x-1\", x, and \"x+1\"
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\n" ); document.write( "Original dimensions:
\n" ); document.write( "height = x-1
\n" ); document.write( "length = x
\n" ); document.write( "width = x+1
\n" ); document.write( "------------------
\n" ); document.write( "Equation:
\n" ); document.write( "Original volume is (x-1)*x*(x+1) = x(x^2-1) = x^3-x
\n" ); document.write( "--------------------
\n" ); document.write( "New dimensions:
\n" ); document.write( "height = 2x-2
\n" ); document.write( "length = x+2
\n" ); document.write( "width = x+3
\n" ); document.write( "-----------------
\n" ); document.write( "Equation:
\n" ); document.write( "new volumn - old volumn = 19 2cm^3
\n" ); document.write( "2(x-1)(x+2)(x+3) - (x^3-x) = 192
\n" ); document.write( "x = 4
\n" ); document.write( "----------
\n" ); document.write( "Answer:
\n" ); document.write( "height = x-1 = 3
\n" ); document.write( "length = x = 4
\n" ); document.write( "width = x+1 = 5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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