document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189705>Question 189705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jane determines that her lawn contains an average of 3.8 grubs per square foot (ft2).  If her rectangular lawn measures 60.4 ft by 80.2 ft, estimate the total number of grubs in her lawn.  Where do I or how do I start?  Do I multiply 60.4 by 3.8 and then multiply 80.2 by 3.8 to get the answer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142355 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Imagine a square 1 ft on each side and 3.8 grubs inside that square.<BR>\n" );
document.write( "Then find the area of her lawn.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60.4%2A80.2+=+4844.1 ALIGN=MIDDLE  ALT=\"60.4%2A80.2+=+4844.1\"   DISABLED_style= \"max-width:90%; height:auto;\" > ft2<BR>\n" );
document.write( "Each of the 1 ft x 1 ft squares in her lawn has 3.8 grubs, so<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.8%2A4844.1+=+18407.5 ALIGN=MIDDLE  ALT=\"3.8%2A4844.1+=+18407.5\"   DISABLED_style= \"max-width:90%; height:auto;\" > grubs in her lawn<BR>\n" );
document.write( "In terms of dimensions, it's<BR>\n" );
document.write( "(grubs/ft2)(ft2/lawn) = grubs/lawn  </SPAN>\n" );
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