document.write( "Question 189712: x^2-x-20>0 \n" ); document.write( "
Algebra.Com's Answer #142352 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-20%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%28x-5%29%3E0\" Factor the left side\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%28x-5%29=0\" Set the left side equal to zero\r
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\n" ); document.write( "\n" ); document.write( "Set each individual factor equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B4=0\" or \"x-5=0\" \r
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\n" ); document.write( "\n" ); document.write( "Solve for x in each case:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-4\" or \"x=5\" \r
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\n" ); document.write( "\n" ); document.write( "So our critical values are \"x=-4\" and \"x=5\" \r
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\n" ); document.write( "\n" ); document.write( "Now set up a number line and plot the critical values on the number line\r
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\n" ); document.write( "\n" ); document.write( "\"number_line%28+600%2C+-10%2C+10%2C-4%2C5%29\"\r
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\n" ); document.write( "\n" ); document.write( "So let's pick some test points that are near the critical values and evaluate them.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is less than \"-4\" (notice how it's to the left of the leftmost endpoint):\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-20%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28-5%29%5E2-%28-5%29-20%3E+0\" Plug in \"x=-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"10%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.\r
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\n" ); document.write( "\n" ); document.write( "So part our solution in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is in between \"-4\" and \"5\":\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-20%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"0%5E2-0-20%3E+0\" Plug in \"x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"-20%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is greater than \"5\" (notice how it's to the right of the rightmost endpoint):\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-20%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"6%5E2-6-20%3E+0\" Plug in \"x=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"10%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.\r
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\n" ); document.write( "\n" ); document.write( "So part our solution in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "Summary:\r
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\n" ); document.write( "\n" ); document.write( "So the solution in interval notation is:\r
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\n" ); document.write( "\n" ); document.write( "() ()\r
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