document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26376>Question 26376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6x + 4(3x - 2) = 6x + 2<BR>\n" );
document.write( "First I used the distributive process which broke it down to this:<BR>\n" );
document.write( "6x + 12x - 8 = 6x + 2<BR>\n" );
document.write( "Then I simplified the 6x and 12x which did this:<BR>\n" );
document.write( "18x - 8 = 6x + 2<BR>\n" );
document.write( "Then I had to get the x's on one side and the numbers on another:<BR>\n" );
document.write( "18x - 6x = 12x<BR>\n" );
document.write( "6x - 6x = 0 <BR>\n" );
document.write( "So the formula looked like this:<BR>\n" );
document.write( "12x - 8 = 2<BR>\n" );
document.write( "From here I became stuck with this. I did not know the next step. Could you please give me a hand? Thank you so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14234 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> next step... add 8 to both sides to give 12x = 10\r<BR>\n" );
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document.write( "now divide both sides by 12 to give x = 10/12\r<BR>\n" );
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document.write( "how simplify this to give x = 5/6\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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