document.write( "Question 189687: How can $6300 be invested, one part at 4% p.a. and the remainder at 5% p.a., so that the simple interest will be the same on each investment?\r
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Algebra.Com's Answer #142333 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let \r
\n" ); document.write( "\n" ); document.write( "x = amount invested at 4%\r
\n" ); document.write( "\n" ); document.write( "y = amount invested at 5%\r
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\n" ); document.write( "\n" ); document.write( "Since $6,300 is invested, this means that \"x%2By=6300\". Solve for \"y\" to get \"y=6300-x\"\r
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\n" ); document.write( "\n" ); document.write( "Also, because we want the simple interest in both investments to be equal, this means that \"0.04x=0.05y\". Multiply both sides by 100 to get \"4x=5y\"\r
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\n" ); document.write( "\n" ); document.write( "\"4x=5y\" Start with the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"4x=5%286300-x%29\" Plug in \"y=6300-x\"\r
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\n" ); document.write( "\n" ); document.write( "\"4x=31500-5x\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"4x%2B5x=31500\" Add \"5x\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"9x=31500\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2831500%29%2F%289%29\" Divide both sides by \"9\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=3500\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So $3,500 needs to be invested at 4%\r
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\n" ); document.write( "\n" ); document.write( "\"y=6300-x\" Go back to the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=6300-3500\" Plug in \"x=3500\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=2800\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So $2,800 is needed to be invested at 5%\r
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