document.write( "Question 189685: Nuts costing $9 per kg are to be mixed with nuts costing $6.5 per kg to make 10 kg of nuts costing $8 per kg. How many kg of nuts costing $9 per kg should be used?
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Algebra.Com's Answer #142330 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let \r
\n" ); document.write( "\n" ); document.write( "x = amount of $9 nuts\r
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\n" ); document.write( "\n" ); document.write( "Since we \"to make 10 kg of nuts\", this gives the first equation \"x%2By=10\".\r
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\n" ); document.write( "\n" ); document.write( "Also, since \"$9 per kg are to be mixed with nuts costing $6.5 per kg to make 10 kg of nuts costing $8 per kg.\", this means that \"9x%2B6.5y=8%2810%29\". Multiply 8 and 10 to get 80. So the equation then becomes \"9x%2B6.5y=80\". Finally, multiply EVERY term by 10 to make every number a whole number. So the equation then becomes \"90x%2B65y=800\"\r
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\n" ); document.write( "\n" ); document.write( "So we have the system of equations:\r
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\n" ); document.write( "\n" ); document.write( "\"system%28x%2By=10%2C90x%2B65y=800%29\"\r
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\n" ); document.write( "\n" ); document.write( "Let's solve by substitution\r
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\n" ); document.write( "\n" ); document.write( "Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.\r
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\n" ); document.write( "\n" ); document.write( "So let's isolate y in the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=10\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=10-x\" Subtract \"x\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x%2B10\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "Since \"y=-x%2B10\", we can now replace each \"y\" in the second equation with \"-x%2B10\" to solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"90x%2B65highlight%28%28-x%2B10%29%29=800\" Plug in \"y=-x%2B10\" into the second equation. In other words, replace each \"y\" with \"-x%2B10\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"90x%2B%2865%29%28-1%29x%2B%2865%29%2810%29=800\" Distribute \"65\" to \"-x%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "\"90x-65x%2B650=800\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"25x%2B650=800\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"25x=800-650\"Subtract 650 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"25x=150\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28150%29%2F%2825%29\" Divide both sides by 25 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=6\" Divide\r
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\n" ); document.write( "\n" ); document.write( "-----------------First Answer------------------------------\r
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\n" ); document.write( "\n" ); document.write( "So the first part of our answer is: \"x=6\"\r
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\n" ); document.write( "\n" ); document.write( "Since we know that \"x=6\" we can plug it into the equation \"y=-x%2B10\" (remember we previously solved for \"y\" in the first equation).\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x%2B10\" Start with the equation where \"y\" was previously isolated.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-%286%29%2B10\" Plug in \"x=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-6%2B10\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y=4\" Combine like terms \r
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\n" ); document.write( "\n" ); document.write( "-----------------Second Answer------------------------------\r
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\n" ); document.write( "\n" ); document.write( "So the second part of our answer is: \"y=4\"\r
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\n" ); document.write( "\n" ); document.write( "-----------------Summary------------------------------\r
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\n" ); document.write( "\n" ); document.write( "So our answers are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=6\" and \"y=4\"\r
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\n" ); document.write( "\n" ); document.write( "This means that 6 kg of $9 nuts and 4 kg of $6.50 nuts are needed
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