document.write( "Question 189682: Factor the polynomial by grouping\r
\n" ); document.write( "\n" ); document.write( "z to the third power subtract 4z to the second power add 3z subtract 12 i grouped them but i have no idea what to do next
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Algebra.Com's Answer #142327 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"z%5E3-4z%5E2%2B3z-12\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28z%5E3-4z%5E2%29%2B%283z-12%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"z%5E2%28z-4%29%2B3%28z-4%29\" Factor out the GCF \"z%5E2\" out of the first group. Factor out the GCF \"3\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28z%5E2%2B3%29%28z-4%29\" Since we have the common term \"z-4\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"z%5E3-4z%5E2%2B3z-12\" factors to \"%28z%5E2%2B3%29%28z-4%29\"
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