document.write( "Question 189681: Stevie is twice as old as his brother. Four years ago he was four times as old as his brother. Find their present ages. Can anyone help me, I'm having a lot of trouble coming up with an equation. I can't thank you guys enough!!
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Algebra.Com's Answer #142326 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let s=Stevie's age and b=Brother's age\r
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\n" ); document.write( "\n" ); document.write( "So this means that \r
\n" ); document.write( "\n" ); document.write( "s-4 = Stevie's age 4 years ago, and\r
\n" ); document.write( "\n" ); document.write( "b-4=Brother's age 4 years ago\r
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\n" ); document.write( "\n" ); document.write( "\"Stevie is twice as old as his brother\" translates to \"s=2b\"\r
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\n" ); document.write( "\n" ); document.write( "\"Four years ago he was four times as old as his brother\" translates to \"s-4=4%28b-4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"s-4=4%28b-4%29\" Start with the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2b-4=4%28b-4%29\" Plug in \"s=2b\"\r
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\n" ); document.write( "\n" ); document.write( "\"2b-4=4b-16\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"2b=4b-16%2B4\" Add \"4\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2b-4b=-16%2B4\" Subtract \"4b\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-2b=-16%2B4\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-2b=-12\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"b=%28-12%29%2F%28-2%29\" Divide both sides by \"-2\" to isolate \"b\".\r
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\n" ); document.write( "\n" ); document.write( "\"b=6\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So Stevie's brother is currently 6 years old. Also, he was 2 years old 4 years ago.\r
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\n" ); document.write( "\n" ); document.write( "\"s=2b\" Go back to the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"s=2%286%29\" Plug in \"b=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"s=12\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So Stevie is currently 12 years old. Four years ago, he was 8 years old. Notice how \"8=2%2A4\" (ie 8 yrs old is 4 times greater than 2 yrs old)
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