document.write( "Question 189616: John is four times as old as Harry. In six years, John will be twice as old as Harry. What are their ages now? \n" ); document.write( "

Algebra.Com's Answer #142288 by Earlsdon(6294) $\"\"$ $\"About$

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Let J = John's present age and H = Harry's present age.
\n" ); document.write( "From the problem description, you can write...
\n" ); document.write( "1) J = 4H \"John is four times as old as Harry\" and...
\n" ); document.write( "2) J+6 = 2(H+6) \"In six years, John will be twice as old as Harry (will be in six years)\"
\n" ); document.write( "Substitute the J = 4H from equation 1) into equation 2) and solve for H.
\n" ); document.write( "2a) (4h)+6 = 2(H+6) Simplify.
\n" ); document.write( "2a) 4H+6 = 2H+12 Subtract 2H from both sides.
\n" ); document.write( "2a) 2H+6 = 12 Subtract 6 from both sides.
\n" ); document.write( "2a) 2H = 6 Finally, divide both sides by 2.
\n" ); document.write( "2a) H = 3 and...
\n" ); document.write( "1) J = 4(3) = 12
\n" ); document.write( "John is 12 years old and Harry is 3 years old.
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