document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26372>Question 26372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve 6x-y=-4; x+2y=7 using substitution method? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14228 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the 1st equation for \"y\": y=6x+4<BR>\n" );
document.write( "Substitute into the 2nd equation, as follows;<BR>\n" );
document.write( "X+2(6X+4)=7<BR>\n" );
document.write( "X+12X+8=7<BR>\n" );
document.write( "13X=-1<BR>\n" );
document.write( "X=-1/13<BR>\n" );
document.write( "Substitut that into y=6x+4<BR>\n" );
document.write( "y=6(-1/13)+4<BR>\n" );
document.write( "y=-6/13-52/13<BR>\n" );
document.write( "y=46/13<BR>\n" );
document.write( "Solution: x=-1/13; y=46/13<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );