document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26252>Question 26252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would this be factored completely?\r<BR>\n" );
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document.write( "128-2a^3\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14227 by </B><A HREF=/tutors/aboutme.mpl?userid=uknouluvme89><B>uknouluvme89(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uknouluvme89><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14227\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 128-2a^3<BR>\n" );
document.write( "factor out a 2<BR>\n" );
document.write( "2(64-a^3)<BR>\n" );
document.write( "since (64-a^3) is a difference of two cubes, we follow the mathematical rules for a difference of two cubes<BR>\n" );
document.write( "2(4-a)(16+4a+a^2)<BR>\n" );
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