document.write( "Question 189602This question is from textbook saxon algebra 2
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\n" ); document.write( "30 over x^2-9 = 2 over x-3.
\n" ); document.write( "I worked it out to: x=12 or x=3
\n" ); document.write( "x=3 is extraneous
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Algebra.Com's Answer #142267 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You are correct. Here's the check\r
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\n" ); document.write( "\n" ); document.write( "Checking \"x=12\"\r
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\n" ); document.write( "\n" ); document.write( "\"30%2F%28x%5E2-9%29+=+2%2F%28x-3%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"30%2F%2812%5E2-9%29+=+2%2F%2812-3%29\" Plug in \"x=12\"\r
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\n" ); document.write( "\n" ); document.write( "\"30%2F%28144-9%29+=+2%2F%2812-3%29\" Square 12 to get 144\r
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\n" ); document.write( "\n" ); document.write( "\"30%2F135+=+2%2F9\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "\"2%2F9+=+2%2F9\" Reduce. Since the equation is true, this verifies that \"x=12\" is a solution.\r
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\n" ); document.write( "\n" ); document.write( "Checking \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"30%2F%28x%5E2-9%29+=+2%2F%28x-3%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"30%2F%283%5E2-9%29+=+2%2F%283-3%29\" Plug in \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"30%2F%289-9%29+=+2%2F%283-3%29\" Square 3 to get 9\r
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\n" ); document.write( "\n" ); document.write( "\"30%2F0+=+2%2F0\" Subtract. Since division by zero is undefined, this means that \"x=3\" is NOT part of the domain. So it is NOT a solution.\r
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