document.write( "Question 189581: Can you please help me solve this? I'm supposed to factor using the formula \"%28a-b%29%28a%5E2-ab%2Bb%5E2%29\" but I'm not exactly sure how to. \"27x%5E3-64\" \n" ); document.write( "
Algebra.Com's Answer #142260 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"27x%5E3-64\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%29%5E3-%284%29%5E3\" Rewrite \"27x%5E3\" as \"%283x%29%5E3\". Rewrite \"64\" as \"%284%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283x-4%29%28%283x%29%5E2%2B%283x%29%284%29%2B%284%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283x-4%29%289x%5E2%2B12x%2B16%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"27x%5E3-64\" factors to \"%283x-4%29%289x%5E2%2B12x%2B16%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"27x%5E3-64=%283x-4%29%289x%5E2%2B12x%2B16%29\"
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