document.write( "Question 189583: Can you please help me solve this? I'm supposed to factor using the formula \"%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29\" or \"%28a-b%29%28a%5E2-ab%2Bb%5E2%29\" but I'm not exactly sure which one, and how to. \"x%5E4-7x%5E2-8\" \n" ); document.write( "
Algebra.Com's Answer #142256 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Looking at \"x%5E4-7x%5E2-8\" we can see that the first term is \"x%5E4\" and the last term is \"-8\" where the coefficients are 1 and -8 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient -8 to get -8. Now what two numbers multiply to -8 and add to the middle coefficient -7? Let's list all of the factors of -8:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -8:\r
\n" ); document.write( "\n" ); document.write( "1,2,4,8\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-4,-8 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -8\r
\n" ); document.write( "\n" ); document.write( "(1)*(-8)\r
\n" ); document.write( "\n" ); document.write( "(2)*(-4)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(8)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(4)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to -7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -7\r
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First NumberSecond NumberSum
1-81+(-8)=-7
2-42+(-4)=-2
-18-1+8=7
-24-2+4=2
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 1 and -8 add up to -7 and multiply to -8\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"x%5E4-7x%5E2-8\", replace \"-7x%5E2\" with \"x%5E2-8x%5E2\" (notice \"x%5E2-8x%5E2\" combines to \"-7x%5E2\". So it is equivalent to \"-7x%5E2\")\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E4%2Bhighlight%28x%5E2-8x%5E2%29%2B-8\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"x%5E4%2Bx%5E2-8x%5E2-8\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E4%2Bx%5E2%29%2B%28-8x%5E2-8%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%28x%5E2%2B1%29-8%28x%5E2%2B1%29\" Factor out the GCF of \"x%5E2\" out of the first group. Factor out the GCF of \"-8\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-8%29%28x%5E2%2B1%29\" Since we have a common term of \"x%5E2%2B1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E4%2Bx%5E2-8x%5E2-8\" factors to \"%28x%5E2-8%29%28x%5E2%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"x%5E4-7x%5E2-8\" factors to \"%28x%5E2-8%29%28x%5E2%2B1%29\" (since \"x%5E4-7x%5E2-8\" is equivalent to \"x%5E4%2Bx%5E2-8x%5E2-8\")\r
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\n" ); document.write( "\n" ); document.write( " Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"x%5E4-7x%5E2-8\" factors to \"%28x%5E2-8%29%28x%5E2%2B1%29\"
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