document.write( "Question 189582: Can you please help me solve this? I'm supposed to factor using the formula \"%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29\" but I'm not exactly sure how to. \"x%5E3%2B64\" \n" ); document.write( "
Algebra.Com's Answer #142255 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"x%5E3%2B64\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%29%5E3%2B%284%29%5E3\" Rewrite \"x%5E3\" as \"%28x%29%5E3\". Rewrite \"64\" as \"%284%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%28%28x%29%5E2-%28x%29%284%29%2B%284%29%5E2%29\" Now factor by using the sum of cubes formula. Remember the sum of cubes formula is \"A%5E3%2BB%5E3=%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Note: in this case, \"A=x\" and \"B=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%28x%5E2-4x%2B16%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3%2B64\" factors to \"%28x%2B4%29%28x%5E2-4x%2B16%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E3%2B64=%28x%2B4%29%28x%5E2-4x%2B16%29\"
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