document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189566>Question 189566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello.  My husband and I are trying to figure out how many cord of wood we have just split.  It's piled into a cone area with a  base area of 19' across and 8' high.  Approximately how many cord do we have???\r<BR>\n" );
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document.write( "Thank you,<BR>\n" );
document.write( "Joanna </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142245 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note: a cord of wood is defined to be 4 feet high by 4 feet wide by 8 feet long which gives a volume of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2A4%2A8=128 ALIGN=MIDDLE  ALT=\"4%2A4%2A8=128\"   DISABLED_style= \"max-width:90%; height:auto;\" > cubic feet.\r<BR>\n" );
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document.write( "I'm assuming that the cone has a base diameter of 19'. Or is the base area 19 square feet? If the base has a diameter of 19', this would then mean that the base radius is 9.5'. So <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=9.5 ALIGN=MIDDLE  ALT=\"r=9.5\"   DISABLED_style= \"max-width:90%; height:auto;\" > (if the assumption is correct). \r<BR>\n" );
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document.write( "What you want to do first is find the volume of the cone\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V=%281%2F3%29pi%2Ar%5E2%2Ah ALIGN=MIDDLE  ALT=\"V=%281%2F3%29pi%2Ar%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > Start with the volume of a cone equation.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V=%281%2F3%29%283.14%29%289.5%29%5E2%288%29 ALIGN=MIDDLE  ALT=\"V=%281%2F3%29%283.14%29%289.5%29%5E2%288%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=9.5 ALIGN=MIDDLE  ALT=\"r=9.5\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=8 ALIGN=MIDDLE  ALT=\"h=8\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Also, replace <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > with 3.14\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V=%281%2F3%29%283.14%29%2890.25%29%288%29 ALIGN=MIDDLE  ALT=\"V=%281%2F3%29%283.14%29%2890.25%29%288%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Square 9.5 to get 90.25\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V=2267.08%2F3 ALIGN=MIDDLE  ALT=\"V=2267.08%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > Multiply\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V=755.693 ALIGN=MIDDLE  ALT=\"V=755.693\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide\r<BR>\n" );
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document.write( "So the volume of the cone is approximately 755.693 cubic feet.\r<BR>\n" );
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document.write( "Now take the volume of the cone and divide it into the volume of one cord of wood to get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=755.693%2F128=5.904 ALIGN=MIDDLE  ALT=\"755.693%2F128=5.904\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So there are about 5 full cords (almost 6) of wood in that pile. </SPAN>\n" );
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