document.write( "Question 189546: Find P(A or B or C) for the given probabilities.
\n" );
document.write( "P(A=0.39, P(B)=0.27,P(c)=0.18
\n" );
document.write( "P(A and B)=0.13,P(A and C)=0.03,P(B and C)=0.09
\n" );
document.write( "P(A and B and C)=0.01
\n" );
document.write( "P(A or B or C)= \n" );
document.write( "
Algebra.Com's Answer #142244 by kev82(151) ![]() You can put this solution on YOUR website! Let Q = A or B\r \n" ); document.write( "\n" ); document.write( "P(A or B or C) = P(Q or C) = P(Q) + P(C) - P(Q and C)\r \n" ); document.write( "\n" ); document.write( "P(Q) = P(A) + P(B) - P(A and B)\r \n" ); document.write( "\n" ); document.write( "P(Q and C) = P((A and C) or (B and C)) = P(A and C) + P(B and C) - P(A and B and C)\r \n" ); document.write( "\n" ); document.write( "P(A or B or C) = P(A)+P(B)-P(A and B)+P(C)-(P(A and C) + P(B and C) - P(A and B and C))\r \n" ); document.write( "\n" ); document.write( "P(A or B or C) = P(A)+P(B)+P(C)-P(A and B)-P(A and C)-P(B and C)+P(A and B and C)\r \n" ); document.write( "\n" ); document.write( "P(A or B or C) = 0.39+0.27+0.18-0.13-0.03-0.09+0.01 = 0.6 \n" ); document.write( " |