document.write( "Question 189557: Use synthetic division to determine f(i) if f(x)=x^3+2x^2-4\r
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document.write( "any help would be appreciated, thank you! \r
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document.write( "oh by the way here are the choices to choose from: \r
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document.write( "A.-5-2i
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document.write( "B.-5+2i
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document.write( "C.-6+i
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document.write( "D.-6-i \n" );
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Algebra.Com's Answer #142235 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First set up the synthetic division table\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Start by bringing down the leading coefficient 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Multiply i by 1 and place the product (which is i) right underneath the second coefficient (which is 2)\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Add i and 2 to get i+2. Place the sum right underneath i.\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Multiply i by i+2 to get \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Add -1+2i and 0 to get -1+2i. Place the sum right underneath -1+2i.\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Multiply i by -1+2i to get \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Add -2-i and -4 to get -6-i. Place the sum right underneath -2-i.\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the remainder is -6-i, this means that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In other words, if we plug \"i\" in for \"x\" into |