document.write( "Question 189557: Use synthetic division to determine f(i) if f(x)=x^3+2x^2-4\r
\n" ); document.write( "\n" ); document.write( "any help would be appreciated, thank you! \r
\n" ); document.write( "\n" ); document.write( "oh by the way here are the choices to choose from: \r
\n" ); document.write( "\n" ); document.write( "A.-5-2i
\n" ); document.write( "B.-5+2i
\n" ); document.write( "C.-6+i
\n" ); document.write( "D.-6-i
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Algebra.Com's Answer #142235 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "First set up the synthetic division table\r
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i|120-4
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\r
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\n" ); document.write( "\n" ); document.write( "Start by bringing down the leading coefficient 1\r
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i|120-4
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1
\r
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\n" ); document.write( "\n" ); document.write( " Multiply i by 1 and place the product (which is i) right underneath the second coefficient (which is 2)\r
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i|120-4
|i
1
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\n" ); document.write( "\n" ); document.write( " Add i and 2 to get i+2. Place the sum right underneath i.\r
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i|120-4
|i
1i+2
\r
\n" ); document.write( "\n" ); document.write( " Multiply i by i+2 to get \"i%5E2%2B2i=-1%2B2i\" and place it right underneath the third coefficient 0\r
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i|120-4
|i-1+2i
1i+2
\r
\n" ); document.write( "\n" ); document.write( " Add -1+2i and 0 to get -1+2i. Place the sum right underneath -1+2i.\r
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i|120-4
|i-1+2i
1i+2-1+2i
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\n" ); document.write( "\n" ); document.write( " Multiply i by -1+2i to get \"-i%2B2i%5E2=-2-i\" and place the product right underneath the fourth coefficient -4\r
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i|120-4
|i-1+2i-2-i
1i+2-1+2i
\r
\n" ); document.write( "\n" ); document.write( " Add -2-i and -4 to get -6-i. Place the sum right underneath -2-i.\r
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i|120-4
|i-1+2i-2-i
1i+2-1+2i-6-i
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\n" ); document.write( "\n" ); document.write( "Since the remainder is -6-i, this means that \"f%28i%29=-6-i\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, if we plug \"i\" in for \"x\" into \"f%28x%29=x%5E3%2B2x%5E2-4\", we'll get \"-6-i\"
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