document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26368>Question 26368</A>: <I><SPAN STYLE=\"word-break: break-all;\"> During rush hour, Fernando can drive 20 miles using the side roads in the same time that it takes to travel 15 miles on the freeway. If Fernando's rate on the side roads is 9 mi/h faster than his rate on the freeway, find his rate on the side roads. Can someone help me figure this out? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14223 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rate on the freeway = x<BR>\n" );
document.write( "Rate on the side road= x+9<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20%2Fx%2B9=15%2Fx ALIGN=MIDDLE  ALT=\"20%2Fx%2B9=15%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" > ---> cross multiply\r<BR>\n" );
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document.write( "15(x+9)=20x<BR>\n" );
document.write( "135+15x=20x<BR>\n" );
document.write( "5x=135<BR>\n" );
document.write( "x=27<BR>\n" );
document.write( "27+9=36\r<BR>\n" );
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document.write( "Hence, his rate on the side road is 36mph and rate on the freeway is 27mph.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
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