document.write( "Question 189537: Adult tickets for a play cost $25 each and children'ts tickets cost $15 each. The total receipts were $7200 and the total attendance ws 400. How many adults and how many children attended? \n" ); document.write( "
Algebra.Com's Answer #142210 by feliz1965(151)\"\" \"About 
You can put this solution on YOUR website!
Let a = adult tickets\r
\n" ); document.write( "\n" ); document.write( "Let c = children tickets\r
\n" ); document.write( "\n" ); document.write( "Then a + c = 400....This is one equation.\r
\n" ); document.write( "\n" ); document.write( "The second equation is 25a + 15c = 7200.\r
\n" ); document.write( "\n" ); document.write( "We have a system of linear equations in two variables.\r
\n" ); document.write( "\n" ); document.write( "a + c = 400
\n" ); document.write( "25a + 15c = 7200\r
\n" ); document.write( "\n" ); document.write( "Can you solve it now?\r
\n" ); document.write( "\n" ); document.write( "I suggest using the substitution method which far easier than any other method.\r
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\n" ); document.write( "\n" ); document.write( "I got your reply.
\n" ); document.write( "Let a = adult tickets
\n" ); document.write( "Let c = children tickets
\n" ); document.write( "Then a + c = 400....This is one equation.
\n" ); document.write( "The second equation is 25a + 15c = 7200.
\n" ); document.write( "We have a system of linear equations in two variables. \r
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\n" ); document.write( "\n" ); document.write( "a + c = 400...Equation A
\n" ); document.write( "25a + 15c = 7200 \r
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\n" ); document.write( "\n" ); document.write( "I will solve for a in Equation A.\r
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\n" ); document.write( "\n" ); document.write( "a = 400 - c\r
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\n" ); document.write( "\n" ); document.write( "I will now plug 400 - c into Equation B for a.\r
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\n" ); document.write( "\n" ); document.write( "25(400 - c) + 15c = 7200\r
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\n" ); document.write( "\n" ); document.write( "10000 - 25c + 15c = 7200\r
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\n" ); document.write( "\n" ); document.write( "-10c = 7200 - 10000\r
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\n" ); document.write( "\n" ); document.write( "-10c = -2800\r
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\n" ); document.write( "\n" ); document.write( "c = -2800/-10\r
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\n" ); document.write( "\n" ); document.write( "c = 280 tickets\r
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\n" ); document.write( "\n" ); document.write( "The number of children tickets is 280.\r
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\n" ); document.write( "\n" ); document.write( "To find the number of adult tickets, we plug 280 for c into EITHER Equation A or Equation B (your choice).\r
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\n" ); document.write( "\n" ); document.write( "I will use Equation A.\r
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\n" ); document.write( "\n" ); document.write( "a + c = 400\r
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\n" ); document.write( "\n" ); document.write( "a + 280 = 400\r
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\n" ); document.write( "\n" ); document.write( "a = 400 - 280\r
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\n" ); document.write( "\n" ); document.write( "a = 120\r
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\n" ); document.write( "\n" ); document.write( "The number of adult tickets is 120.\r
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\n" ); document.write( "\n" ); document.write( "Understand?\r
\n" ); document.write( "\n" ); document.write( "NOTE: The number of children tickets cannot be 250. The correct answer is 280.\r
\n" ); document.write( "\n" ); document.write( "HERE IS THE PROVE:\r
\n" ); document.write( "\n" ); document.write( "adult tickets = 120 x $25 each = $3000\r
\n" ); document.write( "\n" ); document.write( "children tickets = 280 x $15 each = $4200\r
\n" ); document.write( "\n" ); document.write( "Together = $3000 + $4200 = $7200\r
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