document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26209>Question 26209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first side of a triangle is 8 meters longer than twice the second side. The third side is 3 times the second side. The perimeter is 128 meters. Find the lengths of the three sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14219 by </B><A HREF=/tutors/aboutme.mpl?userid=uknouluvme89><B>uknouluvme89(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uknouluvme89><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = second side<BR>\n" );
document.write( "Let 2x+8 = first side<BR>\n" );
document.write( "Let 3x = third side\r<BR>\n" );
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document.write( "the perimeter is the addition of all three sides so:\r<BR>\n" );
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document.write( "x+2x+8+3x = 128<BR>\n" );
document.write( "add the like terms:<BR>\n" );
document.write( "6x+8 = 128<BR>\n" );
document.write( "subtract 8 from both sides of the equation:<BR>\n" );
document.write( "6x=120<BR>\n" );
document.write( "divide both sides by 6 to get:<BR>\n" );
document.write( "x=20\r<BR>\n" );
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document.write( "Hope you understand! </SPAN>\n" );
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