document.write( "Question 189494: Id have a question if x varies inversely as y and x=2 when y=8, and i should find x when y=17 then x=12 or does x=11? \r
\n" ); document.write( "\n" ); document.write( "Another question would be; if y varies directly with x and y=10 when x=15, find y when x=6, so y=1? \r
\n" ); document.write( "\n" ); document.write( "My last question would be; could someone explain this to me; if y varies directly as x and inversely as z^2, and y=3 when x=2 and z=4, what is the value of x when y=9 and z=4? how would i solve this?
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Algebra.Com's Answer #142187 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "For your first question, neither of your answers are correct.\r
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\n" ); document.write( "\n" ); document.write( "If y varies inversely as x, then you can say:\r
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\n" ); document.write( "\n" ); document.write( "where k is called the constant of proportionality. The first task is to determine the constant of proportionality based on the given values of x and y. To do this, substitute the given values and then solve for k.\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by 2:\r
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\n" ); document.write( "\n" ); document.write( "Now you can create the specific relationship for your problem by substituting this newly discovered value for k:\r
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\n" ); document.write( "\n" ); document.write( "And finally, if you need to know the value of x when y = 17, you need to substitute this value in place of y and solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides of the equation by :\r
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\n" ); document.write( "\n" ); document.write( "And that's your answer.\r
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\n" ); document.write( "\n" ); document.write( "The other two problems are done the same way, except that a direct variation looks like:\r
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\n" ); document.write( "\n" ); document.write( "And in your third problem, you have to set up two equations and solve them both.\r
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