document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189287>Question 189287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> select integers for x, -3 < x < 3.\r<BR>\n" );
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document.write( "y=|x| +1  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142167 by </B><A HREF=/tutors/aboutme.mpl?userid=bsmath><B>bsmath(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bsmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If -3<x<3, x=-2, -1, 0, 1, 2.  Since y= absolute value of x +1, and the<BR>\n" );
document.write( "absolute value of x is the positive value of x, x=0, 1, 2.  So, y=1, 2, 3.  <BR>\n" );
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