document.write( "Question 189475: i'm stumped i tried to by making the tops the same but that didn't go anywhere so i made the bottoms the same and that still didn't get me anywhere.
\n" ); document.write( "\"+%28x%2B1%29%2F2x+=+%28x-1%29%2F%282x-1%29+\"
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Algebra.Com's Answer #142148 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+%28x%2B1%29%2F2x+=+%28x-1%29%2F%282x-1%29+\"
\n" ); document.write( "You must multiply each side of the equation by the same
\n" ); document.write( "thing so that the equation is still true.
\n" ); document.write( "What you should multiply each side by is \"2x%2A%282x+-+1%29\"
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\n" ); document.write( "On the left side, the \"2x\"'s cancel, and on the right
\n" ); document.write( "side, the \"2x+-+1\"'s cancel
\n" ); document.write( "\"+%282x+-+1%29%2A%28x%2B1%29+=+2x%2A%28x-1%29+\"
\n" ); document.write( "\"2x%5E2+%2B+x+-+1+=+2x%5E2+-+2x\"
\n" ); document.write( "Subtract \"2x%5E2\" from both sides
\n" ); document.write( "\"x+-+1+=+-2x\"
\n" ); document.write( "\"3x+=+1\"
\n" ); document.write( "\"x+=+1%2F3\" answer
\n" ); document.write( "-------------
\n" ); document.write( "check answer:
\n" ); document.write( "\"+%28x%2B1%29%2F2x+=+%28x-1%29%2F%282x-1%29+\"
\n" ); document.write( "\"+%281%2F3%2B1%29%2F%282%2A%281%2F3%29%29+=+%281%2F3-1%29%2F%282%2A%281%2F3%29-1%29+\"
\n" ); document.write( "\"+%284%2F3%29%2F%282%2F3%29+=+%28-2%2F3%29%2F%28-1%2F3%29+\"
\n" ); document.write( "Multiply both sides by \"3%2F3\"
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\n" ); document.write( "\"4%2F2+=+-2%2F-1\"
\n" ); document.write( "\"2+=+2\"
\n" ); document.write( "OK
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