document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189463>Question 189463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two sides of a triangle have the same length.  the third side measures 5m less than twice the common length.  The perimeter is 11m.  What is the length of the three sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142132 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Two sides of a triangle have the same length. the third side measures 5m less than twice the common length. The perimeter is 11m. What is the length of the three sides?<BR>\n" );
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document.write( "Let x = measure of sides that have common length<BR>\n" );
document.write( "then from \"the third side measures 5m less than twice the common length.\"<BR>\n" );
document.write( "2x-5 = third side<BR>\n" );
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document.write( "Because they gave us the perimeter we have:<BR>\n" );
document.write( "11 = x + x + 2x-5<BR>\n" );
document.write( "11 = 4x-5<BR>\n" );
document.write( "16 = 4x<BR>\n" );
document.write( "4 m = x<BR>\n" );
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document.write( "third side:<BR>\n" );
document.write( "2x-5 = 2(4)-5 = 8-5 = 3 m<BR>\n" );
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document.write( "Lengths of the three sides:<BR>\n" );
document.write( "4m, 4m, and 3m </SPAN>\n" );
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