document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189421>Question 189421</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help.<BR>\n" );
document.write( "The golden ratio.  The ancient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was approximately 8 to 5, the golden ratio.  If the length of a rectangular painting is 2 ft longer than its width, then for what dimensions would the length and width have the golden ratio? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142126 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8/5=(x+2)/x<BR>\n" );
document.write( "5(x+2)=8x<BR>\n" );
document.write( "5x+10-8X=0<BR>\n" );
document.write( "-3X=-10<BR>\n" );
document.write( "X=-10/-3<BR>\n" );
document.write( "X=3.333 IS THE WIDTH.<BR>\n" );
document.write( "3.333+2=5.333 IS THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "8/5=5.333/3.333<BR>\n" );
document.write( "5*5.333=8*3.333<BR>\n" );
document.write( "26.66=26.66<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );