document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189329>Question 189329</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395870933/algebrahomeworkh>Pre-Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to find the volume of a composite figure. The figure Is a cylinder that is 3 inches in height and 3 inches in length. Attached to one end of the cylinder is a cone which is 2 inches in length. The book wants me to find the volume of the composite figure. The following is what I've tried. <BR>\n" );
document.write( "V= pi(r)to the power of 2 x H. <BR>\n" );
document.write( "V= pi (3)to the power of 2 x 3 + 1/2 x 4/3 pi (2) to the power of 3. <BR>\n" );
document.write( "V= pi (9)(3) + 2/3 pi (8)<BR>\n" );
document.write( "V= 27 pi + 16.76 pi = 43.76pi. \r<BR>\n" );
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document.write( " So the answer would of been 43.76 pi. My teacher tells me this is wrong. So, I guess I need a new method for working this problem, and information to help me understand this topic better. Can you help?? \r<BR>\n" );
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document.write( "Thanks<BR>\n" );
document.write( "~Ave<BR>\n" );
document.write( "    </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142124 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am trying to find the volume of a composite figure. The figure Is a cylinder that is 3 inches in height and 3 inches in length. Attached to one end of the cylinder is a cone which is 2 inches in length. The book wants me to find the volume of the composite figure. The following is what I've tried.<BR>\n" );
document.write( "V= pi(r)to the power of 2 x H.<BR>\n" );
document.write( "V= pi (3)to the power of 2 x 3 + 1/2 x 4/3 pi (2) to the power of 3.<BR>\n" );
document.write( "V= pi (9)(3) + 2/3 pi (8)<BR>\n" );
document.write( "V= 27 pi + 16.76 pi = 43.76pi. <BR>\n" );
document.write( ":<BR>\n" );
document.write( "Lets see what I get when I attack this problem<BR>\n" );
document.write( "V = cylinder vol + Cone vol<BR>\n" );
document.write( "V = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2%2Ah ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F3%29%2Api%2Ar%5E2%2Ah ALIGN=MIDDLE  ALT=\"%281%2F3%29%2Api%2Ar%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "I have to assume that one of those 3\" measurements is the diameter, therefore<BR>\n" );
document.write( "r = 1.5 inches<BR>\n" );
document.write( "V = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A1.5%5E2%2A3 ALIGN=MIDDLE  ALT=\"pi%2A1.5%5E2%2A3\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F3%29%2Api%2A1.5%5E2%2A2 ALIGN=MIDDLE  ALT=\"%281%2F3%29%2Api%2A1.5%5E2%2A2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "V = 21.20575 + 4.7124<BR>\n" );
document.write( "V = 25.9 cu/in<BR>\n" );
document.write( ":<BR>\n" );
document.write( "It looks like you got the vol of a sphere instead of the vol of a cone<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Did this make sense to you? </SPAN>\n" );
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