document.write( "Question 189435: the length of a rectangle is 3 m less than five times the width .
\n" ); document.write( "the area of the rectangle is 36 m^2 find the dimensions
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Algebra.Com's Answer #142121 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!

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\n" ); document.write( "We know for rectangle, Area = Length x Width\r
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\n" ); document.write( "\n" ); document.write( "Given:
\n" ); document.write( "Width = x
\n" ); document.write( "Length = 5x-3, 3 meters less than 5 times width
\n" ); document.write( "Area = 36 sq m\r
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\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "36 = (5x-3)(x)
\n" ); document.write( "36 = 5x^2 - 3x
\n" ); document.write( "5x^2 - 3x -36 =0
\n" ); document.write( "Remember:\"system%28a=5%2Cb=%28-3%29%2Cc=%28-36%29%29\"
\n" ); document.write( "By Quadratic,
\n" ); document.write( "Discriminant: \"b%5E2-4ac=-3%5E2-4%285%29%28-36%29=9%2B720=red%28729%29\"
\n" ); document.write( "Then,
\n" ); document.write( "\"x=%28-%28-3%29%2B-sqrt%28729%29%29%2F%282%2A5%29=%283%2B-27%29%2F10\"
\n" ); document.write( "\"x=%283%2B27%29%2F10=30%2F10=red%283meters%29\"
\n" ); document.write( "\"x=%283-27%29%2F10=-24%2F10=-2.4\", discard\r
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\n" ); document.write( "\n" ); document.write( "So, Width=3 meters
\n" ); document.write( "Length = 5(3)-3 = 15-3 = 12 meters\r
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\n" ); document.write( "\n" ); document.write( "Let's check,
\n" ); document.write( "A = L x W
\n" ); document.write( "36sq m = 12 x 3
\n" ); document.write( "36sq.m. = 36 sq. m.\r
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\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo\r
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