document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26353>Question 26353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you graph (x^2+2x-3)/(x+3)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14211 by </B><A HREF=/tutors/aboutme.mpl?userid=mathrebel><B>mathrebel(25)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathrebel><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14211\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the numerator reduces to (x+3)*(x-1); so the (x+3) cancels out, and you end up with a line that is x-1, but it has a hole at x=-3 because it can't be put in the original equation because you will divide by zero. </SPAN>\n" );
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