document.write( "Question 189389: Two pumps can fill a water tank in 45 minutes when working together. Alone, the second pump takes 3 times longer than the first to fill the tank. How long does it take the first pump alone to fill the tank \n" ); document.write( "
Algebra.Com's Answer #142095 by ankor@dixie-net.com(22740)\"\" \"About 
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Two pumps can fill a water tank in 45 minutes when working together.
\n" ); document.write( " Alone, the second pump takes 3 times longer than the first to fill the tank.
\n" ); document.write( " How long does it take the first pump alone to fill the tank?
\n" ); document.write( ":
\n" ); document.write( "Let x = time required for the first pump to fill the tank alone
\n" ); document.write( "then
\n" ); document.write( "3x = time required for the 2nd pump to do it alone
\n" ); document.write( ":
\n" ); document.write( "Write an equation of them working together; let the full tank = 1
\n" ); document.write( "Each pump will do a fraction of the job and will equal 1 when added together
\n" ); document.write( ":
\n" ); document.write( "\"45%2Fx\" + \"45%2F%283x%29\" = 1
\n" ); document.write( "Multiply equation by 3x, results
\n" ); document.write( "3(45) + 45 = 3x
\n" ); document.write( ":
\n" ); document.write( "135 + 45 = 3x
\n" ); document.write( ":
\n" ); document.write( "180 = 3x
\n" ); document.write( "x = \"180%2F3\"
\n" ); document.write( "x = 60 min for pump 1 alone
\n" ); document.write( ":
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\n" ); document.write( "Check solution; (2nd pump requires 3*60 = 180 min alone)
\n" ); document.write( "\"45%2F60\" + \"45%2F180\" =
\n" ); document.write( ".75 + .25 = 1; confirms our solution
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