document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189382>Question 189382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the area of a triangle is 40 cm^2 and the base equals (2h + 6), what is the height?\r<BR>\n" );
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document.write( "Here is what I tried.<BR>\n" );
document.write( "A=1/2bh\r<BR>\n" );
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document.write( "40=1/2(2h + 6)(h)<BR>\n" );
document.write( "40= (h^2 + 3h)(h)<BR>\n" );
document.write( "40= h^3 + 3h^2\r<BR>\n" );
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document.write( "stuck here.  Thanks for the help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142077 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the area of a triangle is 40 cm^2 and the base equals (2h + 6), what is the height? <BR>\n" );
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document.write( "A=(1/2)bh <BR>\n" );
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document.write( "bh = 2A<BR>\n" );
document.write( "h = (2A)/b<BR>\n" );
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document.write( "h = (2*40)/(2h+6)<BR>\n" );
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document.write( "Cross-multiply to get:<BR>\n" );
document.write( "2h^2 + 6h - 80 = 0<BR>\n" );
document.write( "h^2 +3h - 40 = 0<BR>\n" );
document.write( "(h+8)(h-5) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "h = 5 cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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