document.write( "Question 189277: The additive inverse of a number divided by 16 is the same as 1 less than -5 times its reciprocal. Find the number. \n" ); document.write( "
Algebra.Com's Answer #142053 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The additive inverse of a number divided by 16 is the same as 1 less than -5 times its reciprocal. \n" ); document.write( " Find the number. \n" ); document.write( ": \n" ); document.write( "Let x = \"a number\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply equation by -1, get rid of all these negatives: \n" ); document.write( " \n" ); document.write( "Multiply equation by 16x, results: \n" ); document.write( "x^2 = 16(5) + 16x \n" ); document.write( ": \n" ); document.write( "x^2 = 80 + 16x \n" ); document.write( ": \n" ); document.write( "x^2 -16x - 80 = 0 \n" ); document.write( "Factors to: \n" ); document.write( "(x-20)(x+4) = 0 \n" ); document.write( ": \n" ); document.write( "x = +20 \n" ); document.write( "x = -4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in original equation: \n" ); document.write( "x=20 \n" ); document.write( " \n" ); document.write( "-1.25 = -.25 - 1 \n" ); document.write( "and \n" ); document.write( "x=-4 \n" ); document.write( " \n" ); document.write( "+.25 = +1.25 - 1 \n" ); document.write( " |