document.write( "Question 189277: The additive inverse of a number divided by 16 is the same as 1 less than -5 times its reciprocal. Find the number. \n" ); document.write( "
Algebra.Com's Answer #142053 by ankor@dixie-net.com(22740)\"\" \"About 
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The additive inverse of a number divided by 16 is the same as 1 less than -5 times its reciprocal.
\n" ); document.write( " Find the number.
\n" ); document.write( ":
\n" ); document.write( "Let x = \"a number\"
\n" ); document.write( "\"%28-x%29%2F16\" = -5(\"1%2Fx\") - 1
\n" ); document.write( "\"%28-x%29%2F16\" = \"-5%2Fx\" - 1
\n" ); document.write( "multiply equation by -1, get rid of all these negatives:
\n" ); document.write( "\"x%2F16\" = \"5%2Fx\" + 1
\n" ); document.write( "Multiply equation by 16x, results:
\n" ); document.write( "x^2 = 16(5) + 16x
\n" ); document.write( ":
\n" ); document.write( "x^2 = 80 + 16x
\n" ); document.write( ":
\n" ); document.write( "x^2 -16x - 80 = 0
\n" ); document.write( "Factors to:
\n" ); document.write( "(x-20)(x+4) = 0
\n" ); document.write( ":
\n" ); document.write( "x = +20
\n" ); document.write( "x = -4
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solutions in original equation:
\n" ); document.write( "x=20
\n" ); document.write( "\"%28-20%29%2F16\" = -5(\"1%2F20\") - 1
\n" ); document.write( "-1.25 = -.25 - 1
\n" ); document.write( "and
\n" ); document.write( "x=-4
\n" ); document.write( "\"%28-%28-4%29%29%2F16\" = -5(\"1%2F%28-4%29\") - 1
\n" ); document.write( "+.25 = +1.25 - 1
\n" ); document.write( "
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