document.write( "Question 26347: My son is having problems with this type of equation. He has to find out if the linear equation is consistent or inconsistent.Dependant or independant. Example: x+y=4 5x+y=8 How do you graph this equation. How do you work 5x+y=8 to know where to draw the second line of this equation.What would the graph look like .Thanks \n" ); document.write( "
Algebra.Com's Answer #14205 by queenofit(120)![]() ![]() ![]() You can put this solution on YOUR website! first lets look at x+ y = 4 \n" ); document.write( "by writing the equation in slope-intercept form (y=mx+b) \n" ); document.write( "y= -x + 4 you can see that the y intercept is ( 0, 4), this is your first point for this line. Moreover, because the slope, m=-1, (m = your slope and m is the number in front of your x, in this case it is an -1 represented by the - in front of your x). So this line would fall one unit for each unit it moves to the right. In other words, plot (0,4) then move one unit to the right and one unit down and plot another point (1,3) and so on, moving one to the right and one unit down because of the neg x. \n" ); document.write( "As for 5x+y=8, you would do this in the same mannor. put the equation in slope intercept form y=mx+b \n" ); document.write( "y=-5x+8 \n" ); document.write( "your first point would be the y intercept which is (0,8) in this case. since your slope is -5, this line would fall 5 units for every one unit it moves to the right just like we did it above. let your son graph these and see if he can figure out if they are depentant or indepentant of each other from the graph. this is most likely what the instructor wanted him to do. \n" ); document.write( "Tips for graphing : \n" ); document.write( "a) when your slope (m) is positive, the line rises from left to right \n" ); document.write( "b) when your slope (m) is zero, as in y=2, the line is horizontal \n" ); document.write( "c) when your slope (m) is negative (as in your examples), the line falls from left to right. \n" ); document.write( "To find the y intercept of an equation, let x=0 and solve for y. then put it into (0,y)as your point. to find the x intercept let y=0 and solve for x, then (x,0)is your point.\r \n" ); document.write( "\n" ); document.write( "This portion of his algebra is difficult to grasp, however, I cannot stress how important it is that he gets a good understanding of it. He will need it for the higher maths in college, I tutor at college and in High school as well as on this website and you would not believe the amount of students who have graduated high school without the understandings of the math concepts they need to suceed in the college courses. You are a great parent to help him!!!!He just doesn't know how much. I wish all my students had a parent like you.\r \n" ); document.write( "\n" ); document.write( "If you need further assistance, please post again and I will try to help in anyway that I can. \n" ); document.write( " |