document.write( "Question 189313: Mark has 56 coins totalling $7.10. If he has only dimes and quarters, how many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #142027 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! Q+D=56 OR Q=56-D \n" ); document.write( ".25Q+.10D=7.10 \n" ); document.write( ".25(56-D)+.10D=7.10 \n" ); document.write( "14-.25D+.10D=7.10 \n" ); document.write( "-.15D=7.10-14 \n" ); document.write( "-.15D=-6.90 \n" ); document.write( "D=-6.90/-.15 \n" ); document.write( "D=46 IS THE NUMBER OF DIMES. \n" ); document.write( "56-46=10 IS THE NUMBER OF QUARTERS. \n" ); document.write( "PROOF: \n" ); document.write( ".25*10+.10*46=7.10 \n" ); document.write( "2.50+4.60=7.10 \n" ); document.write( "7.10=7.10 \n" ); document.write( " \n" ); document.write( " |