document.write( "Question 288: The sum of the squares of two consecutive integers is 41. Find the integers \n" ); document.write( "
Algebra.Com's Answer #142 by ichudov(507)\"\" \"About 
You can put this solution on YOUR website!
You have two consecutive integers, number and number+1. The sum of their squares is \"number%5E2+%2B+%28number%2B1%29%5E2\". Since it is 41, we have \r
\n" ); document.write( "\n" ); document.write( "\"number%5E2+%2B+%28number%2B1%29%5E2+=+41\" or\r
\n" ); document.write( "\n" ); document.write( "\"number%5E2%2B+%28number%5E2%2B2number%2B1%29+=+41\"\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "\"2number%5E2%2B2number+-40\"\r
\n" ); document.write( "\n" ); document.write( "Solve it using my quadratic solver. (the solution is pretty obvious, 4 and 5, it is just as easy to try the first few numbers without writing an equation)
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